Jankovic goes down to Bartoli at Australian Open

The world no. 1 female tennis player Jelena Jankovic has been sent packing at the Australian Open. Her conquerer was no. 17 ranked French woman Marion Bartoli. This is not the first time that Bartoli has upstaged her higher ranked opponent in a round of 16 match at a Grand Slam.

Back in the Wimbledon tournament of 2007 Bartoli made a charge to the final after having defeated Jankovic.

Bartoli came to the Australian Open in good form after having reached the final in Brisbane. In todays match she was also playing at the top of her game. Bartoli would go on to defeat the top seed 6-1, 6-4.

Bortoli hit 34 winners to Jankovic’s 17. She had 20 unforced errors so was way out in front in the winners to errors ratio.

Jankovic just could not hold serve in this match. She lost serve 5 times and was able to break Bartoli just two times in the match. Jankovic had the chance to get back into the match but just could not stop the run of winners coming from the Bartoli racquet.

This was a great win for the French women. Bartoli advances to play the winner of the all Russian match between the 7th seed Vera Zvonareva and the 10th seed Nadia Petrova.

In the final 16 at the Australian Open women’s draw there are 6 players from Russia. France and Spain with two are the next best represented countries.

Facebook comments: